Question

-10,-6,-2,2 in arithmetic progression

Answer 1

as a=-10 so that d= -6+10=4, -2+6=4, 2+2=4 so it is in A. P

Answer 2

Heya!

Here is yr answer....


Given,

-10 , -6 , -2 , 2

a1 , a2 , a3 , a4


Now,

a = -10 , a2 = -6 , a3 = -2 , a4 = 2

common diff. = d

d = a2 - a1 = a3 - a2

d = -6-(-10) = -2-(-6)

d = -6+10 = -2+6

d = 4 = 4

So, common diff. (d) = 4


Therefore, It's an AP!


Hope it hlpz..