Question

10.6 g of Na2co3 is present in qpp cm3 of its solution. 10 cm3 of this solution is taken into a 1 dm3 conical flask and made upto the mark with distilled water. what is the molarity of the final solution? 1) 1M. 2)0.1M. 3)0.01M. 4) 0.001M​

Answer 1

Explanation:

Aloha !

molarity= mol solute / L solute

mol solute = molarity× L solute

mol solute =10.6×10

=106

Changing into Moles.

≈0.1M

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Answer 2

ANSWER

$\huge\boxed{0.1M}$

Steps

we know that

$morality = \frac{mol \: solute}{solution}$

so

mol solute =morality×solution

so plugging in the values

1.6×10

=106

so if we convert this to moles

we get your answer as 0.1M

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