10
6. In an electrical circuit two resistors of 2 1 and 4 1 respectively are
connected in series to a 6 V battery. The heat dissipated by the 4 resistor
in 5 s will be *
Answers
Answered by
2
Explanation:
Energy dissipated = PtorVI×tor =I
2
Rt Joules
Consider Ohm's law V=IR.
In this case the resistors are connected in series and hence, the total resistance is 4+2=6 ohms. In a series circuit, the current remains the same throughout the circuit and so we use the I
2
Rt Joules formula.
The total current in the circuit is calculated as I=V/R=6/6=1ampere.
Therefore, the power dissipated P across the 4 ohm resistor for 5 s
= 1
2
×4×5=20Joules
Hence, The heat dissipated by the 4 resistor in 5 s will be 20 J.
Similar questions