Question

10-[8-{11+30÷(4-(5-7)}]​

Answer 1

Answer :

◆Simplification

= 10-[8-{11+30÷(4-(5-7)}]

= 10 - [8-{11+30÷(4-(-2)}]

= 10 - [8-{11+30÷(4+2)}]

= 10 - [8-{11+30÷6}]

= 10 - [8-{11+5}]

= 10 - [8-16]

= 10 - [-8]

= 10 + 8

= 18

Thus , 18 is the required answer !

_____________________________

Answer 2

We need to apply BODMAS.

BODMAS is an operation in mathematics that tells us in which order we should solve a problem. The order of operations are-

• Brackets
• Of
• Division
• Multiplication
• Addition
• Subtraction

Now let's solve your question keeping the above in mind.

The problem is ⇒ $10-[8- \{11+30\div (4-(5-7) \}]$

First we solve the simple bracket (which is the smallest bracket).

$10-[8- \{11+30\div (4-(-2) \}]$

Now we apply the integer law which is ⇒ $-(-)=+$

$10-[8- \{11+30\div (4+2) \}]$

$10-[8- \{11+30\div 6 \}]$

Now we do the curly brackets. In this bracket, we shall first do division and then addition.

$10-[8- \{11+5}]$

$10-[8- 16]$

Now we do the box bracket which is the biggest bracket.

$10-[8- 16]$

$10-(-8)$

Now we apply the integer law which is ⇒ $-(-)=+$

$10+8$

$18$

∴ $10-[8- \{11+30\div (4-(5-7) \}]=18$