Question

10.80 rupeez were divided among 45 students and each boys shoul get 22 paise and each girl should get 28 paise . How many boys and girls were present

Answer 1

Let the number of boys receiving money be x and the number of girls be y

• 22x + 28y = 1080                  (1)
• x+y = 45                                 (2)
• Multiply (2) by 22, we get -
• 22x + 22y = 990                     (3)
• Subtracting (3) from (1), we get
• 6y = 90
• y = 15
• Therefore, from (2) we get, x = 30
• Hence, number of boys = 30 and number of girls = 15

Answer 2

Step-by-step explanation:

Given 10.80 rupees were divided among 45 students and each boys should get 22 paise and each girl should get 28 paise . How many boys and girls were present

• Let m and n be number of boys and number of girls  
• So m + n = 45---1
• Also 22m + 28n = 1080
• Now we get 11 m + 14n = 540—2
• Multiply eqn 1 by 11 we get
• 11m + 11n = 495
• 11m + 14n = 540
• Subtracting the equations we get
• So – 3 n = - 45
• Or n = 15
• Now m + n = 45
• Or m + 15 = 45
• Or m = 45 – 15
• Or m = 30
• So 30 boys and 15 girls were present