10.
A 5.0 kg box rests on a horizontal surface. The coefficient of kinene
friction between the box and the surface is 0.5. A horizontal force pune
the box at constant velocity for 10 cm. The work done by the applied
horizontal force and the frictional force are respectively (take g = 10 m/s)
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Answer:
Explanation:
mass of box =5kg
Coefficient of kinetic friction between the box and the surface is =u= 0.5
displacement = 10cm = 0.1m
Solution:
Work done by horizontal force:
w = F .d
where F = mgu
w= 5*10*0.5*0.1
w=2.5joules
Work done by Friction:
w = F .d
where F = mgu
w= 5*10*0.5*0.1
w=2.5joules
hence work is done by friction against the motion so,
w= -2.5joules
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