Question

If x+y+2=0 then find the value of x^3+y^3+8

Answer 1

Step-by-step explanation:

x+y+2=0 =>x+y= -2 Cube on both sides,

${(x + y)}^{3} = { ( - 2)}^{3} = > {x}^{3} + {y}^{3} +$

$3xy(x + y) = - 8 = > {x}^{3} + {y}^{3} + 8 =$

$- 3xy(x + y) = - 3xy( - 2) = 6xy$

Hence the value of x^3+y^3+8 is 6xy. Hope it helps you.