Question

10 a + b is equals to root 3 then 10 a minus b is equals to 1 by root 3 find the a and b

Answer 1

$10a + b = \sqrt{3} \\ \\ 10a - b = \frac{1}{ \sqrt{3} }$

eq 1 - eq 2

$2b = \sqrt{3} - \frac{1}{ \sqrt{3} } \\ \\ 2b = \sqrt{3} - \frac{ \sqrt{3} }{3} \\ \\ 2b = \frac{3 \sqrt{3} - \sqrt{3} }{3} \\ \\ 2b = \frac{2 \sqrt{3} }{3} \\ \\ b = \frac{ \sqrt{3} }{3} \\ \\ b = \frac{1}{ \sqrt{3} }$

putting value of b in 2nd equation

$10a \: - \frac{1}{ \sqrt{3} } = \frac{1}{ \sqrt{3} } \\ \\ 10a = \frac{2}{ \sqrt{3} } \\ \\ a = \frac{1}{5 \sqrt{3} }$