10. A body starts from rest and is found to cover
3 m during the 5th second of its motion.
Find the acceleration if it is uniformly
accelerated.
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Explanation:
Given conditions ⇒
A body is starts at the rest,
∴ Initial Velocity of the body (u) = 0
Now, Distance covered b the body = 3 m.
Time taken by the body = 5 seconds.
∴ Velocity of the body = Distance/Time
= 3/5
= 0.6 m/s.
∴ Final Velocity (v) of the body = 0.6 m/s.
Now, Using the Formula,
Acceleration = \frac{Final Velocity - Initial Velocity}{Time}Acceleration=
Time
FinalVelocity−InitialVelocity
∴ a = \frac{v - u}{t}a=
t
v−u
∴ a = \frac{0.6 - 0}{5}a=
5
0.6−0
∴ a = 0.12 m/s².
Hence, the acceleration of the body is 0.12 m/s².
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