Question

10. A bullet of mass 20 g moving with a speed of 90 m s' enters a wooden block of mass 5 kg
and is stopped after travelling a distance of 60 cm. What is the average resistive force exerted by
the block on the bullet?​

Answer 1

Answer:

Answer is 270N

Explanation:

bcoz we are given that:

u=90

v=0

s=0.6m

So we have v² -u?=2as

therefore a= -u?/2s

so 90*90/2*0.636750

& f=m*a

.. f= 0.04*6750

so f=270n

Answer 2

Answer:

The answer of your question is 270N.