Question

10. A Copper atom has 29 electrons revolving
around the nucleus. A copper ball contains 4 x 1023
atoms. What fraction of the electrons be removed to
give the ball a charge of +9.6 micro C?​

Answer 1

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Answer 2

Solution :

Here  ,

• No of electrons = 29
• Total no of atoms = 4 x 10 ²³

⇒ Total number of electrons ( N) = 29 x 4 x 10²³ = 116 x 10²³

Now ,

• Charge of the ball (q)= 9.6 μ C
• Charge on an electron (e)= 1.6 x 10-¹⁹ C

we know that ,

⇒ q = n x e

⇒ n = q / e

⇒ n = 9.6 x 10-⁶ / 1.6 x 10-¹⁹

⇒ n = 6 x 10¹³

Fraction of electrons to be removed

= n / N

= 6 x 10¹³  / 116 x 10²³

= 0.0517 x 10-¹⁰

= 5. 17 x 10-¹²

The fraction of electron's to be removed is 5.17 x 10-¹² .