Question

10. A man's age is seven times that of his son. In 5 years, he will be four times as old as his son. What are the present ages of the man and his son?

Answer 1

let at present age of son = x years
father age =7x years

after 5 years
son age = (x+5) years
father age = (7x+5) years

father age = 4 times of his son age
7x+5 = 4(x+5)
7x+5 = 4x+20
7x-4x=20-5
3x=15
x=15/3
x= 5
therefore
at present
son age = x = 5 years
father age = 7x = 7*5 = 35 years

Answer 2

Step-by-step explanation:

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