father's age is 3 times the sum of ages of his 2 children after 5 years hisage will be 2 times the sum of agers of his 2 children.findthe age of father
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let the ages of two sons be x1, x2 and the fathers age be y:
3(x1+x2) = y
x1+x2 = y/3
2(x1+x2+10) = y+5
2((y/3)+10) = y+5
(2/3)y +20 = y+5
20-5 = y - (2/3)y
15 = (1/3)y
y = 45
hence the age of father is 45 years.
3(x1+x2) = y
x1+x2 = y/3
2(x1+x2+10) = y+5
2((y/3)+10) = y+5
(2/3)y +20 = y+5
20-5 = y - (2/3)y
15 = (1/3)y
y = 45
hence the age of father is 45 years.
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