Question

10) A person starts a job with some fixed salary and yearly increment.
After 4 years his salary is Rs. 15000 and after 10 years it becomes Rs.
18000. Then find his monthly salary and increment.​

Answer 1

Answer:

Let the starting salary of the man be Rs. x and the fixed annual increment be Rs. y. Then,

Salary after 4 years of service =Rs. (x+4y)

Salary after 10 years of service =Rs. (x+10y)

∴x+4y=1500 (i)

x+10y=1800 (ii)

Substracting equation (i) from equation (ii), we get

6y=300⇒y=50

Putting y=50 in equation (i), we get x=1300.

Hence the starting salary was Rs. 1300 and annual increment is Rs. 50.