Math, asked by Anonymous, 1 month ago

10. A piggy bank contains hundred 50p coins, fifty ? 1 coins, twenty 2 coins and ten 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin
(i) will be a 50 p coin?
(ii) will not be a 5 coin?​

Answers

Answered by itzbangtanbutterfly
15

Answer:

Given: Number of 50 paise coins = 100

Number of 1 rupee coins = 50

Number of 2 rupee coins = 20

Number of 5 rupee coins = 10

So, total number of coins = 100 + 50 + 20 + 10 = 18O

(2) Probability of not 5 rupee coin = 1 - Probability of 5 rupee coin

= 1 - Number of 5 rupee coins/total number of coins = 1 - 10/180 = 1 - 1/18 = 17/18..

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Answered by rawatnikki2003
0

Answer:

Total number of coins in the piggy bank =100+50+20+10=180.

i)

P(50p coin) =

total number of coins

number of 50p coins

=

180

100

P(50p coin) =

9

5

ii)

Number of c 5 coins =10

Number of coins which are not c 5=170

P(coin not being c 5) =

180

170

=

18

17

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