Question

10. A reservoir is in the shape of a frustum of a
right circular cone. It is 8 m across at the top
and 4 m across the bottom. It is 6 m deep. Its
capacity is
A. 176 m2
B. 196 m
D. 110 m
m
C. 200 m​

Answer 1

Answer:

Correct option is

A

176 m

3

Volume of a frustum of a cone =

3

1

πh(R

2

+r

2

+Rr)

Where h is the height and R and r are the radii of the upper and lower ends of a frustum of a cone.

Height h=6 m

Since, the reservoir is 8 m across the top, upper radius R=4 m

Similarly, lower radius r=2m

So, volume of the reservoir =

3

1

×

7

22

×6(4

2

+2

2

+4×2) m

3

=

7

22

×2(16+4+8) m

3

=

7

22

×2×28 m

3

=176 m

3

Hence, the volume of the reservoir is 176 m

3

Explanation:

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