Physics, asked by morecs2000, 1 year ago


10. A solid cube of copper of edge 10 cm subjected to
a hydraulic pressure of 7 * 106 Pa. If Bulk
modulus of copper is 140 GPa, then contraction in
its volume will be
(1) 5 x 10-8 m² (2) 4 x 10-8 m3
(3) 2 x 10-8 m3
(4) 108 m​

Answers

Answered by Anonymous
6

\huge\underline{\underline{\bf \green{Question-}}}

A solid cube of copper of edge 10 cm subjected to a hydraulic pressure of {\sf 7×10^6\:Pa}. If Bulk modulus of copper is 140 GPa, then contraction in its volume will be

\huge\underline{\underline{\bf \green{Solution-}}}

\large\underline{\underline{\sf Given:}}

  • Edge ( l ) = 10cm or 0.1m
  • Hydraulic Pressure \rho = {\sf 7×10^6\:Pa}
  • Bulk modulus ( B ) = 140GPa

\large\underline{\underline{\sf To\:Find:}}

  • Contraction in Volume (∆V)

\large{\boxed{\bf \blue{B = \dfrac{P}{\dfrac{\triangle V}{V}} }}}

\implies{\sf  \triangle V = Change\:in\:volume   \\ \sf \dfrac{\rho V}{B}}

Original Volume ( V ) = l³

\large{\boxed{\bf \blue{ \triangle V =\dfrac{\rho V}{B} }}}

\implies{\sf \dfrac{7×10^6×(0.1)^3}{140×10^9} }

\implies{\bf \red{\triangle V =5×10^{-8}m^3}}

\huge\underline{\underline{\bf \green{Answer-}}}

Contraction in bulk Volume is {\bf \red{5×10^{-8}m^3}}

Answered by jacob909
0

Answer:

5×10^-8 m3 is the answer..

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