10) ABC is an isosceles triangle with AB = AC and AD is an altitude then__________ (a) ∠B ∠C (b) ∠B ∠C (c) ∠B = ∠C (d) None of these
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Step-by-step explanation:
In tringle ABD & ACD
AB=AC (Given)
Angle ADB=Angle ADC (both are right angle)
AD=AD (common)
So both the triangles are congruent
Therefore BD=CD (CPCT)
Angle BAD=Angle CAD (CPCT)
Hence, AD bisects bith BC and Angle A.
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