Question

10. An electric heater has a rating of 800W-220V. Calculate a. its resistance b. electrical energy it consumes in kWh if it is used continuously for 2 hours.

Answer 1

Answer:

Resistance = 60.5 ohm

Energy = 1.6 kilo watt hour

Explanation:

Power = Voltage ²/Resistance

P = V²/R

800 = 220²/R

800 = 48400/R

R = 60.5 ohm

Power = Energy/Time

P = E/T

800 = E/2

E = 1600 watt hour

Here the energy is in watt hour so we have to convert it to kilo watt hour.

For this we will divide it by 1000 because, 1000 watt = 1 kilo watt

So 1 watt = 1/1000 kilo watt.

Therefore, 1600 watt hour = 1.6 kilo watt hour.

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