Question

10. An electron is moving in an uniform magnetic field perpendicularly with velocity v. The force exerts on
electron will be
(a) eV/B b) eVB (C) eB/V (d) VB/e​

Answer 1

Answer:

Given:- B=0.1N/amp−m

v=10

5

m/s

q

e

=1.6×10

−19

c

θ=90

o

=Angle between velocity and magnetic field

Lorentz force on electron is given by,

F

=

F

E

+

F

M

where

F

E

=0=Force due to electric field ....(because there is no electric field)

F

=0+

F

M

=

F

M

Where F

M

=Magnetic force on electron,

and

F

M

=q

e

v×B=q

e

vBsin(θ)=q

e

vBsin(90

o

)=1.6×10

−19

×10

5

×0.1×1

∴

F

=

F

M

=1.6×10

−15

N