Question

10. An object 5 cm in length is held 25 cm away from a converging lens of focal length
10 cm. Draw the ray diagram and find the position, size and the nature of the
image formed.
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Answer 1

Answer:Here's your answer

Explanation:

An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed. V = 50/3 cm. hi = -10/3 cm.

Answer 2

Answer:

Postition of image = At a distance 16.66 cm away from lens on right side.

Size of image = 3.3 cm on right side of lens

Nature of image = inverted and real.

Explanation:

Given,

An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm.

To find:   The position(v), size and the nature of the image formed.

Solution:

From sign convention,

Distance of image(u) = - 25 cm

Height of object (H_o) = + 5cm

Focal length of the lens ( f) = + 10 cm

Applying Len's formula,

1/v - 1/u = 1/f

1/v - 1/(-25) = 1/10

1/v = 1/10 - 1/25

1/v = (5 - 2)/50

1/v = 3/50

or, v= 50/3 = 16.66 cm

From Magnification formula,

m = - v / u = -16.66/25 = -0.66

Also, magnification can be given as:

m = height of image / height of object

or, m = H_i / H_o

or, -0.66 = H_i / 5

or, H_i = -0.66 * 5 = -3.3 cm

Since, Height of image is negative we can say that image formed will be inverted and real. Ray diagram is attached.

Therefore, Postition of image = At a distance 16.66 cm away from lens on right side.

Size of image = 3.3 cm on right side of lens

Nature of image = inverted and real.