Question

You have three resisters of values 2Ω , 3Ω and 5Ω . How will you join

them so that total resistance is more than -
7Ω​

Answer 1

Answer:

science

Explanation:

In order to get more than 7Ω resistance from three resistors 2Ω, 3Ω and 5Ω, we need to connect them in series as shown in the diagram.

Equivalent resistance in series combination is given by   Req=R1+R2+R3

⟹ Req=2+3+5=10Ω   (which is greater than 7Ω)



Answer 2

Answer:

In order to get more than 7Ω resistance from three resistors 2Ω, 3Ω and 5Ω, we need to connect them in series as shown in the diagram.

Equivalent resistance in series combination is given by   Req=R1+R2+R3

⟹ Req=2+3+5=10Ω   (which is greater than 7Ω)

Explanation: