Question

10. Consider the following figure. CuSO4 Zn Case-I HCl Zn Case-II CuSO4 Fe Case-III NaOH Al Case-IV In which of the given cases a gas is released? (1) I and III (2) II and III (3) I and II (4) II and IV

Answer 1

Answer:Both I and IV is correct, So the 4th option is correct

Explanation: Equation I contains the gas Hydrogen which will be released after the reaction:

HCl + Z = ZCl + H

Equation IV is also correct as Aluminium will react with aqueous Sodium Hydroxide to give Sodium Aluminate with rapid evolution of H2 gas:

NaOH + Al = NaAlO + H