Physics, asked by Priyanshujd, 11 months ago

10
(D) IUNO VIDIO
12.a
A dipole having dipole moment p is placed in front of a solid uncharged conducting sphere as shown in
the diagram. The net potential at point A lying on the surface of the sphere is :
А
(A) kpcoso
(B) kpcos º
(C) zero
(D) 2kp coso
r2
Adanbora.​

Answers

Answered by knjroopa
1

Explanation:

Given A dipole having dipole moment p is placed in front of a solid uncharged conducting sphere as shown in  the diagram. The net potential at point A lying on the surface of the sphere is

  • So we need to find the net potential.
  • So we have Vp = Kp cos theta / r^2
  • So there will be an induced charge. Also for a conductor, there will be no electric field inside the conductor.
  • At the inside point electric field E = 0
  • So Vo = Vp + V induced charge.
  • The positive and negative charge will be equal and opposite in magnitude.
  • So V induced =0 for any point inside the conducting sphere.
  • So Vp = (Kp cos theta / R^2)
  • So total potential Vo = Vp + 0
  •                                    = kpcos theta / r^2
  • Both dipole moment and vector r are aligned in one direction.
  • So we have Vp + 0 = kp cos 0 / R^2
  •                                    = kp (1) / R^2
  • So Va = Vo = (kp / R^2)
  •                                             Now cos φ = base / hypotenuse
  •                                                                  = r / R
  •                                          Or R = r / cos φ
  • So  Va = Vo = Kp / r^2 cos^2 φ

Reference link will be

https://brainly.in/question/3741690

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