Question

bond order of na2 with formula and correct method
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Answer 1

Answer:

Bond order is 1.

Because Na has 1valance electron.

so,Na2 has 2 valence electron.

it means one lone pair .

so,bond order is 1.

Answer 2

The bond order of $Na_2$ is 1.

Given: $Na_2$.

To find: We have to find the bond order.

Solution:

Na is an alkali metal having an atomic number 11.

The total number of electrons in $Na_2$ is 11+11=22.

The electronic configuration of $Na_2$ is given as-

${\sigma1s}^{2} {\sigma {1s}^{.} }^{2} {\sigma2s}^{2} {\sigma {2s}^{.} }^{2} {\sigma2px}^{2} {\pi 2py}^{2} {\pi 2pz}^{2} {\pi {2py}^{.} }^{2} {\pi {2pz}^{.} }^{2} {\sigma {2px}^{.} }^{2} {\sigma3s}^{2}$

Thus it has a total of 14 electrons in bonding orbitals and 12 electrons in antibonding bandits.

Thus bond order will be-

$\frac{14 - 12}{2} = 1$

Bond order of $Na_2$ is 1.