Math, asked by Animeshmorya, 9 months ago

10. एक समचतुर्भुज की प्रत्येक. भुजा 34 मी और एक विकर्ण 32 मी है तो
(i) दूसरा विकर्ण (ii) क्षेत्रफल और (iii) ऊँचाई ज्ञात करें।
please guy's answer​

Answers

Answered by shivanshi77
1

(I) diagonals of rhombus bisect each other at right angle so

32/2=16

by using Pythagoras triplet

h^2=p^2+b^2

34^2=p^2+16^2

1156=p^2+256

√900=p

30×2=p

60=p it is length of second diagonal

(ii) area=1/2×diagonal1×diagonal 2

1/2×32×60=960

iii) area =base×height

960=34×height

960/34=28.11=height

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