Question

10. Find a Pythagorean triplet whose one member
is 323. for 8th how came 36​

Answer 1

Answer:

$pythagorean \: triplet = 2m \: \: \: \: \: \: \: {m}^{2} - 1 \: \: \: \: \: \: \: {m}^{2} + 1$

${m}^{2} - 1 = 323 = > {m}^{2} = 324 = > m = \sqrt{324} = 18$

So, triplet = 36, 323, 325

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