Question

10. Find the angles of a triangle which are
in the ratio 4:3.2​

Answer 1

Answer:

Let the common ratio be "x"

We know that sum of all angles inside a triangle is 180⁰.

Therefore, 4x + 3x + 2x = 180⁰

9x = 180⁰

x = 20⁰

Using this we can find the value of the angles.

So, the angles are 4(20)⁰, 3(20)⁰ and 2(20)⁰.

The angles are 80⁰, 60⁰ and 40⁰

Answer 2

$\bold{\boxed{Answer:-}}$

$4x = 80°$

$3x = 60°$

$2x = 40°$

$\bold{\boxed{Step-by-step\:\:explanation:-}}$

Let the angles in ratio 4:3:2 be 4x , 3x and 2x

Sum of all angles of a triangle is 180°

So , 4x + 3x + 2x = 180°

9x = 180°

x = 180 ÷ 9

x = 20°

.

Let's verify the result !

We know that the sum of all angles of a triangle is 180°

So, 4x + 3x + 2x = 180°

x = 20°

Then , 4(20) + 3(20) + 2(20) = 180°

4×20 + 3×20 + 2×20 = 180°

80° + 60° + 40° = 180°

180° = 180°

LHS (Left hand side) = RHS (Right hand side)

$Hence ,\:\:verified$

.

.

• $Therefore$ , the first angle 4x of the triangle is

4x = 4(20)

= 4×20 = 80°

.

• Second angle 3x of the triangle is

3x = 3(20)

3×20 = 60°

.

• Third angle 2x of the triangle

2x = 2(20)

2× 20 = 40°

.

$Done\:!$