10. Find the first terms and common difference of an AP, whose t8
=3 and
t12=52
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4
Answer:
The first term is -331/4
The common difference is 49/4
Step-by-step explanation:
t8 =3 and
t12=52
t8 = a + 7d = 3 --(1)
t12 = a + 11d = 52 --(2)
from eq.--(1)
a + 7d = 3
a = 3 - 7d--(3)
Put value of a in eq.--(2)
3 - 7d + 11d = 52
4d = 52 - 3
4d = 49
d = 49/4
Now put d in eq.--(3)
a = 3 - 7(49/4)
= (12 - 343)/4
= -331/4
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