Question

10. Find the number of zeroes at the end of the product of first 250 natural numbers.
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Answer 1

ANSWER:

62

STEP BY STEP:

1×2×3×....250=250!

Number of zeroes in product of n numbers=

(n/5)+(n/5^2)+(n/5^3)

Numbers of zeroes in product of 250

Numbers=(250/5)+(250/5^2)+250/5^3)

=(50)+(250/25)+(250/125)

=(50)+(10)+(2)

=(60)+(2)

=62

Hence,the zeroes at the end of the product of first 250 natural numbers is 62