Question

10. Find the value of k for which the quadratic equation
2x square- kr +k=0 has equal roots.​

Answer 1

Step-by-step explanation:

2x^2-kr+k=0

2x^2-k(r-1)=0

1-8k=0

k= 1/8

Answer 2

Answer:

Step-by-step explanation:

According to nature of roots if

D= 0 roots are equal

Therefore: b^2-4ac= 0

According to equation

(-k)^2-4(2)(k) =0

K square -8k =0

K(k-8)=0

K=0(neglected) & k=8

Hence answer is [k=8]