10. For every litre of petrol, one car travels x km and another car travels
5 km more than the first. If the first car uses 4 litres more than the
second car in converting 400 km, frame an equation for the
statement to find x. What is the value of x?
Not Ansed
Answers
Answer:
car A travels x km for every litre of petrol.while car B travels (x+5)km for every litre of petrol.
if car A uses 4 litres of petrol more than car B in covering 400km, find the number of litres of petril used by car B for the journey.
Car A's consumption - Car B consumption = 4 liters
400/x - 400/x-5=4
multiply by x(x+5) to clear the denominators, results:
400(x+5) - 400x = 4x(x+5)
400x + 2000 - 400x = 4x^2 + 20x
Combine like terms, A quadratic equation
4x^2 + 20x - 2000 = 0
simplify, divide by 4
x^2 + 5x - 500 = 0
Factors to
(x+25)(x-20) = 0
the positive solution
x = 20 km/liter for Car A
then
25 km/liter for Car B
therefore car B=400/25=16 liters for 400 km
Hope this helps...
Answer:
Step-by-step explanation:
Car A's consumption - Car B consumption = 4 liters
400%2Fx - 400%2F%28%28x%2B5%29%29 = 4
:
multiply by x(x+5) to clear the denominators, results:
400(x+5) - 400x = 4x(x+5)
400x + 2000 - 400x = 4x^2 + 20x
:
Combine like terms, A quadratic equation
4x^2 + 20x - 2000 = 0
;
simplify, divide by 4
x^2 + 5x - 500 = 0
:
Factors to
(x+25)(x-20) = 0
:
the positive solution
x = 20 km/liter for Car A
then
25 km/liter for Car B
therefore
Car B: 400%2F25 = 16 liters for 400 km journey
:
:
Confirm this solution by finding the consumption of Car A
400/20 = 20 liters, 4 liters more