Question

10. From 8p2 - 11p - 50 take away 40 - 2p2 + 7p

Answer 1

$\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=8p^2-11p-50-\left(40-2p^2+7p\right)}$

$\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=8p^2-11p-50-40+2p^2-7p}$

$\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=8p^2+2p^2-11p-7p-50-40}$

$\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-11p-7p-50-40}$

$\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-18p-50-40}$

$\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-18p-90}$