Math, asked by rawathirawathi1, 2 months ago

10. From 8p2 - 11p - 50 take away 40 - 2p2 + 7p

Answers

Answered by ExploringMathematics
0

\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=8p^2-11p-50-\left(40-2p^2+7p\right)}

\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=8p^2-11p-50-40+2p^2-7p}

\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=8p^2+2p^2-11p-7p-50-40}

\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-11p-7p-50-40}

\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-18p-50-40}

\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-18p-90}

Similar questions