Q.17 ABCD is a trapezium in which AD||BC, ∠퐴퐵퐶 =900 AD=16cm, AC=41cm and
BC=40cm. Find the area of the trapezium.
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Step-by-step explanation:
The area of the given trapezium ABCD = 252 cm²
Step-by-step explanation:
For better understanding of the solution see the attached figure of the problem :
Given : m∠ABC = 90°, AD = 16 cm, AC = 41 cm and BC = 40 cm
To find : Area of trapezium ABCD
Solution : Since, m∠ABC is 90°
So, AB is the height of the trapezium ABCD
Now, to find AB : By using Pythagoras theorem in ΔABC
AC² = AB² + BC²
41² = AB² + 40²
⇒ AB² = 41² - 40²
⇒ AB = 9 cm
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