Question

10 g of acetic acid is dissolved in water to give 100 ml of solution its normality will be​

Answer 1

To answer and calculate this value, let us take into consideration that w/v be the given percentage.

So, let percentage be = w/v.

Now, 10 percent certainly does be equivalent to 10 gram of Acid that is mixed in water (100 ml).

This would also make 100 g of Acetic Acid = 1000 ml of water.

Now focusing on mole concept, we know that

1 mole Acetic acid = 60 g by mass.

100 g Acetic acid = 100 / 60 = 1.67 moles.

So in 1 l of water it is certain that 1.67 moles of Acetic acid is present.

Now for acetic acid we have 1 Normality = 1 Mole

So 10 percent Normality = 1.67 .