Question

10 g of Caco3 sample is completely decomposed
into CaO and CO2. If weight of CaO formed is 3.6 g,
then percentage purity of sample is​

Answer 1

Answer:

Explanation:

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Answer 2

10 g of Caco3 sample is completely decomposed into CaO and CO2.

let's see chemical reaction..

CaCO3 → CaO + CO2

here it is clear that one mole of CaCO3 yielded one mole of CaO.

or, 100g of CaCO3 yielded 56g of CaO

[we know, molar mass of CaCO3 = 100g/mol and molar mass of CaO = 56 g/mol]

or, 10g of CaCO3 yielded 5.6g of CaO.

but here only 3.6g of CaO is yielded.

now, % purity of sample = actual yield/theoretical yield × 100

= 3.6g/5.6g × 100

= 64.26 %

hence, sample is 64.26% pure.