10 g of ethanol (molecular weight 46) is disolved in 50g of water calculate:
a) mole fraction of ethanol.
b) molality of solution.
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Answer:
mass of ethanol =10 g
molar mass [C2H5OH]=46
mass of water = 50 g
molar mass of H2o = 18
moles of C2H5OH= 10 ÷46
=0.22 mol
moles of H2O = 50÷ 18
= 2.78 mol
mole fraction [c2h5oh] = 0.22/[0.22+2.78]
= 0.22/3
= 0.073
molality = mass of solute× 1000/ molar mass × mass of solvent[in gram]
=10×1000/46×50
=10000/2300
= 4.35 m [ mol/kg]
hope it helps
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ajimonmathaip2v16a:
Thank you so much.
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