Question

10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be:
(a) 3 mol
(b) 4 mol
(c) 1 mol
(d) 2 mol

Answer 1

2H²+O²--->2H²O

this implies two moles of hydrogen reacts with one mole of oxygen to give two moles of water

Moles of hydrogen given=10/2=5

Moles of oxygen given=64/32=2

Therefore we have five moles of hydrogen and two moles of oxygen.

FINDING THE LIMITING REAGENT:

We know that two mole of hydrogen reacts with one mole of oxygen.

So five moles of hydrogen reacts with 2.5 moles of oxygen.

But we have only 2 moles of oxygen, so oxygen is the limiting reagent.

Now we know that one mole of oxygen gives two moles of water.

So two moles of oxygen gives 4 moles of water.

So ans is (b)