10 g of NaOH is added to 50 mL of 0.1 M aqueous solution and volume is finally made 100 ml. Calculate the molarity of resulting solution.
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Answer:
2.25M
Explanation:
V1=V2 =50mL or 0.05L
M1= n/V1
n=(10/40)=0.25
V1=50/1000=0.05L
therefore, M1=0.25/0.05= 5 molar
M2=0.1 molar (given)
M1V1+M2V2 = M3V3
5*50+0.1*50 = M3*100
M3= 2.55M
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