Question

10 gm of CaCO3 =___ mole? Step by step solving.​

Answer 1

Molar Mass of CaCO3 = 40+12+48 = 100gms

Since , 100gm CaCO3 = 1 mole

$\implies$ 1 gm = $\frac{1}{100}$ moles

$\implies$ 10gm = $\frac{10}{100}$ = 0.1 moles

Answer 2

Answer:

0.1 moles mate........