Question

10 gram Bullet moving at 200 m per second stop after penetrating 5 cm of wooden plank the average force exerted on the bullet will be

Answer 1

refer to the attachment

Answer 2

given
mass=10g=10/1000=0.01kg
initial speed=u=200m/sec
final velocity=0m/s
s=5cm=5/100=0.05
from third equation v^2-u^2=2as
0^2-(200)^2=2a*0.05
-40000=a/10
a=-40000m/s^2
from newton second law
f=ma
=0.01*(-400000)
=0.01*-400000
=-4000n



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