Question

10 gram caco3 ko tapt karne pr kitna gram cao prapt hoga?

Answer 1

Question :

If 10 g of CaCO₃ is heated , how much gram of CaO is liberated ?

Answer :

Molecular mass of CaCO₃ can be calculated by finding the atom mass of each atom

Ca = 40 .

C = 12

O = 16

CaCO₃ = 40 + 12 + ( 16×3 )

⇒ 52 + 48

⇒ 100

The molecular mass is 100 g .

Molecular mass of CaO

= 40 + 16

= 56

100 grams of CaCO₃ 56 grams of CaO

Then 1 gram of CaCO₃ will libeate 56/100 gram of CaO

Then 10 grams of CaCO₃ will liberate 56/100 × 10 grams of CaO

Hence the mass of CaO liberated = 56/100 × 10 ⇒ 56/10 ⇒ 5.6

5.6 grams of CaO is liberated .

NOTE :

First find the molecular mass of both .

Then calculate the answer using normal unitary method .

The atomic mass should be given in the question .

Answer 2

Holla user .

we know that

atomic weight of caco3=100.0

and atomic weight of cao=56.0

now referred the attachment below⬇️⬇️⬇️