Math, asked by anirudhsureshkumar67, 2 months ago

10 house had in a neighbourhood are sorted according to their monthly income are given below

16500, 21700, 18600, 21050, 19500, 17000, 21000, 18000, 22000, 75000

a: what is the mean income of these 10 families ?

b: How many families have montly income less than mean income . prove that in such situation this average is suitable or not ?​

Answers

Answered by jsjejrdjejrjjfjejfk
0

Answer:

ncjekdkfowldkfjsnfnchehducujsrlgkfpwodkfjnenenfjfcjfjdkdkeksjfjcjcjddjcjejfjcjwjdjfjdnrnfjdejfjfjddjdjdjdjdkdkdjwjwnwnwnnejsjdj

Answered by cathem1001
0

Answer:

a) 25035

b) 9 families

Step-by-step explanation:

a) Mean = sum / number

= 250350 / 10

= 25035

b) 9 families have monthly income less than the mean income.. so in this situation this is not a suitable average

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