Math, asked by singhrukmani92, 6 months ago


10. How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed
to fit in a rectangular region whose length and breadth are respectively:
(a) 200 cm and 144 cm
(b) 80 cm and 48 cm​

Answers

Answered by bhoomikatavarageri
4

Answer:

Given that,

the length and breadth of the tiles are 12 cm and 5 cm

Therefore, the area of the tiles

= length \times breadth

= 12 cm \times 5 cm

= 60 cm2

Now, (a) For 100 cm and 144 cm rectangular region,

Area of region = length \times breadth

= 14,400 cm2

Therefore, the number of tiles needed = \frac{14,400}{60}=240 tiles

(b) For 70 cm and 36 cm rectangular region,

Area of region = length \times breadth

= 70 cm \times 36 cm

= 2520 m2

Required number of tiles = \frac{2520}{60}=42

Answered by Anonymous
10

Answer:

We have:-

  • Dimension of rectangular room = 200 cm × 144 cm.
  • Dimension of the tile = 12 cm × 5 cm.
  • The tiles are needed to cover the floor.

What To FinD:-

  • No. of tiles needed?

Solution:-

Here,

i) No. of tiles needed:

\large\rm{ = \dfrac{Area \: of \: the \: floor}{Area \: of \: the \: tile} }

The floor and the tiles are in the shape of a rectangle. Hence, the area is given by: Length × Breadth.

Plugging them to find no. of tiles:

= 200 cm × 144 cm / 12 cm × 5 cm

= 40 × 12 tiles

= 480 tiles.

Therefore:-

The required no. of tiles needed to cover the entire rectangular floor is 480 tiles

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