Question

10) If A=4x2 + y2 + 7xy, B=7x2 – 6y2 – 10xy, C=x2 + y2 + xy
find i) A-B+C ii) 2A+C.​

Answer 1

Answer:

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Step-by-step explanation:

$\bold\red{A=4x {}^{2} + y {}^{2} + 7xy} \\ \\ \bold\blue{B=7x {}^{2} - 6y {}^{2} - 10xy }\\ \\ \bold\pink{C=x{}^{2} + y {}^{2} + xy} \\ - - - - - - - - - - \\ i) A-B+C \\ \\ \red{4x {}^{2} + y {}^{2} + 7xy} - (\blue{7x {}^{2} - 6y {}^{2} - 10xy } ) + \pink{x{}^{2} + y {}^{2} + xy} \\ \\ \red{4x {}^{2} + y {}^{2} + 7xy} \blue{ - 7x {}^{2} + 6y {}^{2} + 10xy } \pink{ + x{}^{2} + y {}^{2} + xy} \\ \\ 4x {}^{2} - 7 {x}^{2} + {x}^{2} + y {}^{2} + 6y {}^{2} + {y}^{2} + 7xy + 10xy + xy \\ \\ \bold\green{ - 2 {x}^{2} + 8 {y}^{2} + 18xy} \\ - - - - - - - - - - \\ ii) 2A+C\\ \\ 2(\red{4x {}^{2} + y {}^{2} + 7xy}) + \pink{x{}^{2} + y {}^{2} + xy} \\ \\ \red{8 {x}^{2} + 2 {y}^{2} + 14xy} + \pink{x{}^{2} + y {}^{2} + xy} \\ \\ 8 {x}^{2} + {x}^{2} + 2 {y}^{2} + {y}^{2} + 14xy + xy \\ \\\bold\green{ 9 {x}^{2} + 3 {y}^{2} + 15 xy}$