10. If an angle of a parallelogram is four-fifths of its
adjacent angle, find the angles of the parallelogram.
Answers
Answer:
<A= <C= 100°
<B=<D= 80°
Step-by-step explanation:
let the ||gm be ABCD
let the ||gm be ABCD so, the sum of adjacent angles is 180°
let the ||gm be ABCD so, the sum of adjacent angles is 180°here <A=<C= x (VERTICALLY OPPOSITE)
let the ||gm be ABCD so, the sum of adjacent angles is 180°here <A=<C= x (VERTICALLY OPPOSITE) HERE <B= <D= 4x/5 ( VERTICALLY OPPOSITE)
let the ||gm be ABCD so, the sum of adjacent angles is 180°here <A=<C= x (VERTICALLY OPPOSITE) HERE <B= <D= 4x/5 ( VERTICALLY OPPOSITE) so let the angle be x and 4x/5,
let the ||gm be ABCD so, the sum of adjacent angles is 180°here <A=<C= x (VERTICALLY OPPOSITE) HERE <B= <D= 4x/5 ( VERTICALLY OPPOSITE) so let the angle be x and 4x/5, x+4x/5 = 180°
let the ||gm be ABCD so, the sum of adjacent angles is 180°here <A=<C= x (VERTICALLY OPPOSITE) HERE <B= <D= 4x/5 ( VERTICALLY OPPOSITE) so let the angle be x and 4x/5, x+4x/5 = 180°9x= 180°×5
let the ||gm be ABCD so, the sum of adjacent angles is 180°here <A=<C= x (VERTICALLY OPPOSITE) HERE <B= <D= 4x/5 ( VERTICALLY OPPOSITE) so let the angle be x and 4x/5, x+4x/5 = 180°9x= 180°×5x= 100°
let the ||gm be ABCD so, the sum of adjacent angles is 180°here <A=<C= x (VERTICALLY OPPOSITE) HERE <B= <D= 4x/5 ( VERTICALLY OPPOSITE) so let the angle be x and 4x/5, x+4x/5 = 180°9x= 180°×5x= 100°therefore <A= <C= 100°
let the ||gm be ABCD so, the sum of adjacent angles is 180°here <A=<C= x (VERTICALLY OPPOSITE) HERE <B= <D= 4x/5 ( VERTICALLY OPPOSITE) so let the angle be x and 4x/5, x+4x/5 = 180°9x= 180°×5x= 100°therefore <A= <C= 100° <B=<D= 80°
Step-by-step explanation:
Step-by-step explanation:
A° = 4/5B°
A°+B°=180
4/5A + 1A = 180
4/5A+5/5A = 180
1/5A = 180 / 9
1/5A = 20
A= 100
B= 80