10. If tan (A+B) = √3 and tan (A - B) = 1/√3 0°< A+B < 90°; A > B, find A and B.
Answers
Answered by
0
Answer:
tan ( A + B )
= √3
= tan 60°
Therefore, A + B = 60° - ( i )
tan ( A - B )
= 1/√3
= tan 30°
Therefore, A - B = 30° - ( ii )
From i and ii
A + B = 60
A - B = 30
----------------
2A + 0 = 90
A = 90/2
A = 45°
Putting A = 45° in equation ii
A - B = 30°
45 - B = 30
B = 45 - 30
B = 15°
Therefore, A = 45° and B = 15°
Similar questions