Question

10. In A ABC, right-angled at C if tan A = 1/√3, find the value of sin A cos B + cos Asin B.​

Answer 1

Answer:

1

Step-by-step explanation:

Tan A = 1/√3

A=30°

Therefore, B=60°

Now, sinA.cosB+cosA.sinB=sin(A+B)

sin(30°+60°)=sin90°=1.