10. In a four-digit number, the digit in ones place is 1 more than that in the tens place.
The digit in thousands place is 4 more than that in hundreds place. The digit in
hundreds place is twice of the digit at tens place. If the digit at the tens place is 2, find
the number
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a+6 5a a a+ 1
1000(a+6) + 500a + 10 a +a +1
= 1511a + 6001
At a = 1
7512
At a= 0
6001
Therefore the two possible solutions are 7512 or 6001.
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