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In a leap year, the probability of having 53 Sundays or 53 Mondays
a 2/7
b 3/7
c 4/7
d 5/7
Answers
Answered by
0
Answer:
option c is the answer I hope
Answered by
5
Step-by-step explanation:
we know that there are 366 days in a leap year
= 52 weeks +2 days
These 2 days can be:
- {sun,mon}
- {mon,Tue}
- {tue,wed}
- {wed,Thurs}
- {Thurs,Fri}
- {Fri,sat}
{sat,sun}.
n(s)=7
now,
out of these 7 outcomes the favourable outcomes are 2.{sun,mon},{sat,sun}.
n(a)=2
required probability p(a)=n(a)/n(s)=2/7
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